In the reaction CH_3COOH xrightarrow{PCl_5} ( | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction sequence is as follows:$1$. $CH_3COOH + PCl_5 \rightarrow CH_3COCl + POCl_3 + HCl$. Product $(A)$ is Acetyl chloride $(CH_3COCl)$.$2$

Vedclass · Accepted Answer

Methylamine

Vedclass · Answer

(C) The reaction sequence is as follows:$1$. $CH_3COOH + PCl_5 \rightarrow CH_3COCl + POCl_3 + HCl$. Product $(A)$ is Acetyl chloride $(CH_3COCl)$.$2$. $CH_3COCl + NH_3 \rightarrow CH_3CONH_2 + HCl$. Product $(B)$ is Acetamide $(CH_3CONH_2)$.$3$. $CH_3CONH_2 + NaBrO \rightarrow CH_3NH_2 + Na_2CO_3 + NaBr$. This is the Hofmann bromamide degradation reaction.Product $(C)$ is Methylamine $(CH_3NH_2)$.

In the reaction $CH_3COOH$ $\xrightarrow{PCl_5} (A)$ $\xrightarrow{NH_3} (B)$ $\xrightarrow{NaBrO} (C)$,the final product $(C)$ is

Similar Questions

Gabriel phthalamide synthesis is used for the preparation of :-

Product $(A)$ is

The conversion of propan$-1-$ol to $n-$butylamine involves the sequential addition of reagents. The correct sequential order of reagents is:

What is formed when $RCN$ is treated with sodium and alcohol?

Which of the following amines cannot be prepared by Gabriel phthalimide synthesis?

Vedclass Test Series

Exam Paper Generator

Online Exam Module